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sin =9/15 . Find tan 0

Sin 915 Find Tan 0 class=

Sagot :

rossy1248

Answer:

c. 9/12

Step by step explanation.

Given: sin = 9/15

and,

[tex]sin = \frac{opp.}{hyp.} [/tex]

[tex]tan = \frac{opp.}{adj.} [/tex]

thus, find adj. side

by using Pythagoras theorem

[tex] {c }^{2} = {a}^{2} + {b}^{2} [/tex]

then,

let adj. side be a^

[tex] {a}^{2} = {c}^{2} - {b }^{2} \\ {a}^{2} = {15 }^{2} - {9}^{2} \\ {a}^{2} = 144 \\ a = 12[/tex]

thus,

adj. side is 12

then,

tan of the angle = 9/12

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