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an amplifier has an input resistance of 100k a short-circuit transconductance of 10 mA/V and an output resistance of 100k. Find the open-circuit voltage gain

Sagot :

Answer:

The open circuit voltage gain is [tex]A_{vo}=-10^{3}[/tex]

Explanation:

Given data is input resistance of an amplifier is [tex]R_{in}=100k[/tex]Ω and output resistance of an amplifier is [tex]R_{o} =100k[/tex]Ω.

Trans conductance of an amplifier is [tex]g_{m}=10mA/V[/tex]

Thus Open circuit voltage gain is

[tex]A_{vo} =-g_{m}R_{o}[/tex]

[tex]A_{vo}=-10[/tex]×[tex]10^{-3}[/tex]×100×[tex]10^{3}[/tex]

Since 1m=[tex]10^{-3}[/tex] and 1k=[tex]10^{3}[/tex]

Thus,

[tex]A_{vo}=-1000[/tex]

[tex]A_{vo}=-10^{3}[/tex]

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