Answer:
The standard form of the ellipse is [tex]\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1[/tex].
Step-by-step explanation:
The major axis of the ellipse is located in the y axis, whereas the minor axis is in the x axis. The center of the ellipse is the midpoint of the line segment between vertices, this is:
[tex](h, k) =\frac{1}{2}\cdot V_{1} (x,y) + \frac{1}{2}\cdot V_{2} (x,y)[/tex] (1)
If we know that [tex]V_{1} (x,y) = (4,0)[/tex] and [tex]V_{2}(x,y) = (4, 14)[/tex], then the coordinates of the center are, respectively:
[tex](h,k) = \frac{1}{2}\cdot (4, 0) + \frac{1}{2}\cdot (4,14)[/tex]
[tex](h,k) = (2,0) + (2, 7)[/tex]
[tex](h, k) = (4, 7)[/tex]
The length of each semiaxis is, respectively:
[tex]a = \sqrt{(1 - 4)^{2}+(7-7)^{2}}[/tex]
[tex]a = 3[/tex]
[tex]b = \sqrt{(4-4)^{2}+(0-7)^{2}}[/tex]
[tex]b = 7[/tex]
The standard equation of the ellipse is described by the following formula:
[tex]\frac{(x-h)^{2}}{a^{2}}+ \frac{(y-k)^{2}}{b^{2}} = 1[/tex]
Where:
[tex]h[/tex], [tex]k[/tex] - Coordinates of the center of the ellipse.
[tex]a[/tex], [tex]b[/tex] - Length of the orthogonal semiaxes.
If we know that [tex]h = 4[/tex], [tex]k = 7[/tex], [tex]a = 3[/tex] and [tex]b = 7[/tex], then the standard form of the ellipse is:
[tex]\frac{(x-4)^{2}}{9} + \frac{(y-7)^{2}}{49} = 1[/tex]
