kikivanderwal
Answered

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please factor and find the zeros of each relation (18 marks)

C. y = 30x^2 + 44x +16
D. y = 10x^2 + 60x + 80

Sagot :

sreedevi102

Answer:

[tex]C. \ \frac{-2}{3} , \ \frac{-4}{5}\\\\D. \ -2, \ -4[/tex]

Step-by-step explanation:

C.

[tex]30x^2 + 44x +16 = 0\\\\2(15x^2 + 22 + 8) = 0\\\\2(15x^2 + 12x + 10x + 8) = 0\\\\2(3x(5x + 4)+2(5x + 4))=0\\\\2((3x + 2)(5x + 4)) = 0\\\\Zeroes : 3x + 2 = 0 => x = \frac{-2}{3}\\[/tex]

             [tex]5x+ 4 = 0 => x = \frac{-4}{5}[/tex]

D.

[tex]10x^2 + 60x +80 = 0\\\\10(x^2 + 6x + 8)= 0\\\\10(x^2 + 4x + 2x + 8)=0\\\\10(x(x+4)+2(x+4))=0\\\\10((x+2)(x+4))=0\\\\Zeroes : x + 2 = 0 =>x = -2[/tex]

            [tex]x + 4 = 0 => x= -4[/tex]

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