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Use the square root property to solve for x in the following equation (x-3)^2-10=15

Sagot :

If you were to solve for x by using the square root property, your ANSWER would be x=8,-2

(x – 3)² – 10 = 15

[tex] {x}^{2} - 6x + 9 - 10 = 15[/tex]

[tex] {x}^{2} - 6x - 1 = 15[/tex]

[tex] {x}^{2} - 6x - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 1 - 15 = 0[/tex]

[tex] {x}^{2} + 2x - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8x - 16 = 0[/tex]

[tex]x \times (x + 2) - 8(x + 2) = 0[/tex]

[tex](x + 2) \times (x - 8) = 0[/tex]

[tex]x + 2 = 0[/tex]

[tex]x - 8 = 0[/tex]

so,

[tex]x1 = - 2[/tex]

[tex]x2 = 8[/tex]