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HELP PLEASE!!!!!!!
140 grams of lead (II) nitrate are dissolved in water then mixed with a solution containing 75 grams of sodium chloride. The reaction creates the precipitate, lead (II) Chloride, and a solution of sodium nitrate. How many grams of lead (II) Chloride can be produced given the initial amount of lead (II) nitrate?


Sagot :

Answer:

    Try a grams calculator, Its pretty to nd one :D

Explanation:

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