peridot2000
Answered

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What is the equation of a line that is perpendicular to y = 3x -2 and passes
through the point (6, 8)?
O A. y= -1/3x+10
O B. y= -1/3x + 4
O C. y= 1/3x+6
O D. y= -1/3x+8

Sagot :

Answer:

A. y=-1/3x+10

Step-by-step explanation:

Perpendicular gradients(slopes) are negative reciprocals so

m=-1/3  then use the point (6,8) to find the equation of the line

y=mx+b

8=(-1/3)(6)+b

8=-2+b

b=10

y=-1/3x+10

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