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Find the equation of the line passing through the point (-6,4) that is perpendicular to the line 5x+3y=5

Sagot :

sqdancefan

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Answer:

  3x -5y = -38

Step-by-step explanation:

The equation of the perpendicular line can be formed by swapping the coefficients of x and y in the given equation, negating one of them. The new constant will be the one that lets the given point satisfy the equation.

  given: 5x +3y = 5

  perpendicular: 3x -5y = constant

At the given point, the constant is ...

  3(-6) -5(4) = -18 -20 = -38

So, the desired equation is ...

  3x -5y = -38

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