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Sagot :

Answer:

A has greater volume.

Greater by [tex]43in^3[/tex]

Step-by-step explanation:

[tex]volume \ of \ can = \pi r^2 h[/tex]

[tex]r_A = 3 in, \ h_A = 6 in\\Volume_A = \pi \times 9 \times 6 = 169.65 = 170 in^3\\\\\\r_B = 2.25in , \ h_B = 8\\Volume_B = \pi \times 5.0625 \times 8 = 127.23 = 127in^3[/tex]

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