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Given the vertices of a triangle ABC below, find the midpoint and length of the midsegment. Give your length in simplified radical form.

Given The Vertices Of A Triangle ABC Below Find The Midpoint And Length Of The Midsegment Give Your Length In Simplified Radical Form class=

Sagot :

Answer:

Midpoint of AC = (-1, 1)

Midpoint of BC = (1, -2)

Length of the midsegment = [tex]\sqrt{13}[/tex]

Step-by-step explanation:

Vertices of a triangle ABC are A(0, 5), B(4, -1) and C(-2, -3).

Midpoint of segment AC = [tex]\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}[/tex]

                                         = [tex](\frac{0-2}{2},\frac{5-3}{2})[/tex]

                                         = (-1, 1)

Midpoint of BC = [tex](\frac{4-2}{2},\frac{-1-3}{2})[/tex]

                         = [tex](1,-2)[/tex]

Length of the mid segment = [tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

                                              = [tex]\sqrt{(-1-1)^2+(-2-1)^2}[/tex]

                                              = [tex]\sqrt{4+9}[/tex]

                                              = [tex]\sqrt{13}[/tex]

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