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In the fastest measured tennis serve, the ball left the racquet at 73.14 m/s . A served tennis ball is typically in contact with the racquet for 32.0 ms and starts from rest. The direction of the velocity of the ball just after it left the racquet is the positive x direction. Assume constant acceleration. Part A What was the x component of the ball's acceleration during this serve

Sagot :

oladayoademosu

Answer:

2.286 km/s²

Explanation:

Since acceleration a = (v - u)/t where u = initial horizontal velocity of ball = 0 m/s (since it starts from rest), v = final horizontal velocity of ball at serve = 73.14 m/s and t = time taken for serve = 32.0 ms = 0.032 s

Substituting the values of the variables into the equation, we have

a = (v - u)/t

a = (73.14 m/s - 0 m/s)/0.032 s

a = 73.14 m/s/0.032 s

a =  2285.625 m/s²

a = 2.285625 km/s²

a ≅ 2.286 km/s²

So, the x - component of the ball's acceleration during the serve is 2.286 km/s²

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