noelJ0721
Answered

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Write a function rule for the area A(h) of a parallelogram whose base is 3 units more than its height h.

A. A(h) = h2 + 3
B. A(h) = h2 + 3h
C. A(h) = h2 + 3h + 3
D. A(h) = h + 3h

Sagot :

Answer:  h^2+3h   (Choice B)

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Work Shown:

height = h

base = h+3, since the base is 3 more than the height

area = base*height

area = h*(h+3)

area = h*h + h*3

area = h^2+3h

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