Answered

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complete the square to rewrite y=x^2-6x+2 in vertex form then state whether the vertex is a maximum or a minimum and give its ordinates

Sagot :

EPSTER1

Answer:

[tex]y=(x-3)^2-7[/tex]

Minimum

(-3,-7)

Step-by-step explanation:

[tex]y=x^2 -6x+2[/tex]

[tex]b=-6[/tex]

[tex]\frac{b}{2} =(-3)^2=9[/tex]

[tex]y+7=x^2-6x+9[/tex]

[tex]y=(x-3)^2-7[/tex]

-7 is a minimum.

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