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Sagot :
Answer:
48
Step-by-step explanation:
[tex]a = 12, \ b = 6, \ c = 3\\\\b^2 - c^2 + (a+ b+c) = 6^2 - 3^2 + (12 +6+3) = 36-9+21 = 48[/tex]
Answer:
2-12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
Simplify: 1
Eliminate redundant parentheses
2−12+(++)
b^{2}-1c^{2}+(a+b+c)
b2−1c2+(a+b+c)
2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
Solution: 2−12+++
b^{2}-1c^{2}+a+b+c
b2−1c2+a+b+c
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