Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable solutions to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Word problem in Algebra - Two boys, Shawn and Curtis, went for a walk, Shawn began walking 20 seconds earlier than Curtis. Shawn walked at a speed of 5 feet per second. Curtis walked at a speed of 6 feet per second. For How many seconds had Shawn been walking at the moment when the two boys had walked the same distance?



Sagot :

tclmcMK
So first you should simplify it.
Shawn (S) - 5 ft. per sec
Curtis (C) - 6 ft. per sec
     1 sec        2 s         3 s         4s        5s          6s
S     25 ft       30 ft       35 ft      40 ft      45 ft      50 ft
C     6 ft        12 ft       18 ft      24 ft      30 ft      36 ft
So we keep going on with this table until we find two numbers that match, which is 30. Then we look back at the question. We want to find how many seconds Shawn was at when the hit the same distance as Curtis (30 ft). Yet be sure to keep in mind that Shawn started 20 seconds earlier. So the answer is 2 seconds.
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.