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An insurance company has provided you with a sample of paid claims. The sample includes the following claims: 192, 113, 200, 287, and 225. What are the mean and the variance respectively of this sample rounded to nearest whole number

Sagot :

Answer:

The mean of this sample is 203.

The variance of this sample is 3154.

Step-by-step explanation:

Mean:

Sum of all values divided by the number of values.

In this case:

[tex]M = \frac{192 + 113 + 200 + 287 + 225}{5} = 203.4[/tex]

Rounding to the nearest whole number, 203.

Variance:

Sum of the difference squared between each value and the mean, divided by the number of values. So

[tex]V = \frac{(192-203.4)^2 + (113-203.4)^2 + (200-203.4)^2 + (287-203.4)^2 + (225-203.4)^2}{5} = 3153.8[/tex]

Rounding to the nearest whole number, 3154.

The mean of this sample is 203.  The variance is 3154.

The variance of this sample is 3154.

Mean is given by,

[tex]M=\frac{192+113+200+287+225}{5}[/tex]

M=203.4

Sum of all values divided by the number of values.

In this case:

[tex]M=\frac{192+113+200+287+225}{5}\\M=203.4[/tex]

Rounding to the nearest whole number, 203.

What is the variance?

Some of the differences squared between each value and the mean are divided by the number of values. So

[tex]V=\frac{(102-203.4)^2+(113-203.4)^2+.......+(225-203.4)^2}{5}\\V=3153.8[/tex]

Rounding to the nearest whole number, 3154.

To learn more about the variance visit:

https://brainly.com/question/25639778

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