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Monochromatic light falling on two very narrow slits 0.048mm apart. Successive fringes on a screen 5.00m away are 6.5cm apart near the center of the pattern.What is the wavelength and frequency of the light?

Sagot :

hamzaahmeds

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

[tex]Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}[/tex]

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

[tex]\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}[/tex]

λ = 5.85 x 10⁻⁷ m = 585 nm

Now, the frequency can be given as:

[tex]f = \frac{c}{\lambda}[/tex]

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\[/tex]

f = 5.13 x 10¹⁴ Hz

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