Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Step-by-step explanation:
New Note 2
Given coordinates:
B(1,2)
E(-5,3)
A(-6,3)
Part A, isosceles triangle
Need to find lengths of sides
BE^2 = ((-5-1)^2+(3-2)^2) = 36+1 = 37
BA^2 = ((-6-1)^2+(-3-2)^2) = 49+25 = 74
EA^2 = ((-6-(-5))^2+(-3-3)^2) = 1+ 36 = 37
Since BE^2 = EA^2, BE=EA, or triangle BEA is isosceles, with vertex at E.
Part B, find point R so that BEAR is a sqare
Need to show that the vertex angle, BEA is a right angle.
BA is diagonal and E is 90° if
BE^2 + EA^2 = BA^2
or
37+37 = 74
Hence angle BEA is right anglesd, and the two legs are eaual with length sqrt(37)
To find point R, we find the translation from point E to point B, i.e. from the vertex to end of one of the legs.
EB = B - E = (1-(-5))-(2-3) = <6,-1>
To find point R, apply this translation to the end of the other leg, i.e. point A,
R=A(-6,-3) + <6,-1>=R(0,-4)
Check:
RE (diagonal)^2 = ((0-(-5))^2+(-4-3)^2) = 25+49 = 74 checks
RB^2 = ((0-1))^2+(-4-2)^2) = 1+36 = 37 checks
RA^2 = ((0--(-6))^2+(-4-(-3))^2) = 36+1 = 37 checks
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.