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Sagot :
Answer:
The correct answer is -
Parental - BB and bb
F1
Genotypes: 100% Bb
F2
Genotypes: ¼ BB, ½ Bb, ¼ bb
Explanation:
It is given that a cross between a brown and a silver-blue mink produces all brown offspring and it is only possible if brown is dominant over silver blue in true breed cross, assume brown trait is represented by B and silver-blue is b then parents will be
BB and bb
B B
b Bb Bb
b Bb Bb
Cross between F1 individuals: Bb cross Bb
gametes : B, b and B, b
B b
B BB Bb
b Bb bb
the genotype of F2 : 1:2:1 = ¼ BB, ½ Bb, ¼ bb
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