Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A card is drawn at random from an ordinary pack of playing cards. What is the probability that it is neither a face card nor a black card? 16/52 = 4/13 10/52 = 5/26 14/52 = 7/26 20/52 = 5/13

Sagot :

stigawithfun

Answer:

20 / 52 = 5 / 13

Step-by-step explanation:

Probability(P) is the likelihood of occurrence of an event. It is given by;

P = total number of favourable outcomes ÷ total number of possible outcomes

In a pack of playing cards, there are 52 cards altogether.

Therefore, the total number of possible outcomes = 52

To get the probability that a card drawn at random is neither a face nor a black card, the following should be noted.

i. There are 12 face cards in the pack. These are the kings (4 cards), queens(4 cards) and the jacks (4 cards).

Therefore, number of cards that are not face cards = 52 - 12 = 40

ii. Black cards are half of the total number of cards = 26.

These black cards contain half of the kings, queens and jacks cards = 6 which are already included in the face cards. Therefore, the remaining black cards will be 26 - 6 = 20

Neither a face card nor a black card = 40 - 20 = 20 [number of favourable outcomes]

The probability of getting neither a face card nor a black card is

=> total number of favourable outcomes ÷ total number of possible outcomes

=> 20 / 52 = 5 / 13

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.