Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A card is drawn at random from an ordinary pack of playing cards. What is the probability that it is neither a face card nor a black card? 16/52 = 4/13 10/52 = 5/26 14/52 = 7/26 20/52 = 5/13

Sagot :

Answer:

20 / 52 = 5 / 13

Step-by-step explanation:

Probability(P) is the likelihood of occurrence of an event. It is given by;

P = total number of favourable outcomes ÷ total number of possible outcomes

In a pack of playing cards, there are 52 cards altogether.

Therefore, the total number of possible outcomes = 52

To get the probability that a card drawn at random is neither a face nor a black card, the following should be noted.

i. There are 12 face cards in the pack. These are the kings (4 cards), queens(4 cards) and the jacks (4 cards).

Therefore, number of cards that are not face cards = 52 - 12 = 40

ii. Black cards are half of the total number of cards = 26.

These black cards contain half of the kings, queens and jacks cards = 6 which are already included in the face cards. Therefore, the remaining black cards will be 26 - 6 = 20

Neither a face card nor a black card = 40 - 20 = 20 [number of favourable outcomes]

The probability of getting neither a face card nor a black card is

=> total number of favourable outcomes ÷ total number of possible outcomes

=> 20 / 52 = 5 / 13

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.