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Sagot :
Th matrix is missing. The matrix is :
[tex]\begin{bmatrix}1 &-4 &4 \\ -4 &16 & 4 \end{bmatrix}[/tex]
Solution :
The column of the matrix are [tex]\begin{bmatrix}1\\ -4\end{bmatrix}[/tex] , [tex]\begin{bmatrix}-4\\ 16\end{bmatrix}[/tex], [tex]\begin{bmatrix}4\\ 4\end{bmatrix}[/tex]
Now each of them are vectors in [tex]$IR^2$[/tex]. But [tex]$IR^2$[/tex] has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.
Therefore, the column of the given matrix does not form the [tex]\text{linearly independent set}[/tex] as the set contains [tex]\text{more vectors}[/tex] than there are entries in each vector.
Therefore, option (D) is correct.
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