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A hot metal is placed in 100.0 g sample of water and it causes the temperature of the water to increase from 25 C to 27 C. How many joules of energy did the water absorb from the metal?

Sagot :

Answer: [tex]836.8\ J[/tex]

Explanation:

Given

Mass of water in the sample is [tex]m=100\ g[/tex]

Temperature changes from [tex]25^{\circ}C[/tex] to [tex]27^{\circ}C[/tex]

Change in temperature is [tex]\Delta T=27-25=2^{\circ}C\ \text{or}\ 2\ K[/tex]

We know, specific heat of water is [tex]c=4.184\ J/g-K[/tex]

Heat absorbed is given by

[tex]\Rightarrow Q=mc\Delta T\\\Rightarrow Q=100\times 4.184\times 2\\\Rightarrow Q=836.8\ J[/tex]

Thus, water absorbs [tex]836.8\ J[/tex] of heat from hot plate.