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in garden peas, yellow seeds (y) are dominant to green seeds (y), and inflated pods (i) are dominant to constricted pods (i). suppose you have crossed yyii parents with yyii parents. draw the f1 punnett square and predict the expected f1 phenotype(s). list the genotype(s) of gametes produced by f1 individuals. draw the f2 punnett square. based on this punnett square, predict the expected phenotype(s) in the f2 generation and the expected frequency of each phenotype.

Sagot :

marianaegarciaperedo

Complete question:

In garden peas, yellow seeds (Y) are dominant to green seeds (y), and inflated pods (I) are dominant to constricted pods (i).

Suppose you have crossed YYII parents with yyii parents.

  1. Draw the F1 Punnett square and predict the expected F1 phenotype(s).
  2. List the genotype(s) of gametes produced by F1 individuals. Draw the F2 Punnett square.
  3. Based on this Punnett square, predict the expected phenotype(s) in the F2 generation and the expected frequency of each phenotype.  

Answer:

  1. F1 phenotype ⇒ 100% plants heterozygous for both traits, expressing yellow seeds and inflated pods, YyIi.
  2. F1 gametes ⇒ YI, Yi, yI, yi
  3. F2 Phenotype ⇒
  • 9/16 are expected to be plants with yellow seeds and inflated pods,    Y-I-
  • 3/16 are expected to be plants with yellow seeds and constricted pods, Y-ii
  • 3/16 are expected to be plants with green seeds and inflated pods, yyI-
  • 1/16 are expected to be plants with green seeds and constricted pods, yyii

Explanation:

Available data:

  • yellow seeds (Y) are dominant to green seeds (y)  
  • inflated pods (I) are dominant to constricted pods (i)

1st Cross:

Parentals)       YYII           x         yyii

Gametes) YI, YI, YI, YI            yi, yi, yi, yi

Punnett square)   YI        YI         YI        YI

                    yi   YyIi    YyIi      YyIi      YyIi

                    yi   YyIi    YyIi      YyIi      YyIi

                    yi   YyIi    YyIi      YyIi      YyIi

                    yi   YyIi    YyIi      YyIi      YyIi

F1) 100% of the progeny is expected to be heterozygous for both traits, expressing yellow seeds and inflated pods, YyIi.

2nd Cross:

Parentals)      YyIi            x          YyIi

Gametes) YI, Yi, yI, yi              YI, Yi, yI, yi

Punnett square)    YI         Yi          yI         yi

                    YI     YYII      YYIi      YyII       YyIi

                    Yi     YYIi      YYii      YyIi       Yyii

                    yI      YyII      YyIi       yyII       yyIi

                    yi      YyIi       Yyii      yyIi       yyii

F2) Genotype

  • 1/16 are expected to be YYII
  • 2/16 are expected to be YYIi
  • 1/16 are expected to be YYii
  • 2/16 are expected to be YyII
  • 4/16 are expected to be YyIi
  • 2/16 are expected to be Yyii
  • 1/16 are expected to be yyII
  • 2/16 are expected to be yyIi
  • 1/16 are expected to be yyii

      Phenotype

  • 9/16 are expected to be plants with yellow seeds and inflated pods,    Y-I-
  • 3/16 are expected to be plants with yellow seeds and constricted pods, Y-ii
  • 3/16 are expected to be plants with green seeds and inflated pods, yyI-
  • 1/16 are expected to be plants with green seeds and constricted pods, yyii

Here we've got a condition, in which an inexperienced pea has traits that include the colour of the seed, and the nature of the pod, wherein the Yellow colour seed (Y) is dominant over the inexperienced colour seed (y), and the inflate pods (I) is dominant over the constricted pods (i).

When we make a pass among true-breeding mother and father having yellow colour seed, and inflated pods with true-breeding determine have inexperienced colour seed and constricted pods, then withinside the F1 technology we get -

  1. The genotype of a true-breeding determines having a yellow colour seed, and inflated pOds=YY||.
  2. The genotype of a true-breeding determined to have inexperienced colour seed and constricted pods = yyii.
  3. A pass among YYII (Yellow, inflated) x yyii (Green, constricted).
  4. Gametes are made out of a mother and father having genotype YY|I=YI.
  5. Gametes are made out of a mother and father having genotype i = Yi.

1st cross :

Parental YYII                  x           yyii

Gametwes YI,YI,YI,YI               yi,yi,yi,yi

Punnet square  YI         YI           YI            YI

                    yi  YyIi      YyIi        YyIi           YyIi

                    yi  YyIi       YyIi       YyIi           YyIi

                    yi   YyIi      YyIi        YyIi          YyIi

                    yi   YyIi      YyIi        YyIi          YyIi

100% pure progeny is obtained.

2nd cross :

Parents : YyIi         x           YyIi

Gametes: YI, Yi, yI, yi                  YI, Yi, yI, yi

F2) Genotype ratios :

  1. 1/16 are anticipated to be YYII 2/16 are anticipated to be YYli
  2. 1/16 are anticipated to be YYii
  3. 2/16 are anticipated to be Yyll 4/16 are anticipated to be Yyli
  4. 2/16 are anticipated to be Yyii
  5. 1/16 are anticipated to be yyll
  6. 2/16 are anticipated to be yyli 1/16 are anticipated to be yyii

Phenotype ratio :

  1. 9/16 are anticipated to be vegetation with yellow seeds and inflated pods, Y-I
  2. 3/16 are anticipated to be vegetation with yellow seeds and constricted pods, Y-ii.
  3. 3/16 are anticipated to be vegetation with inexperienced seeds and inflated pods, yyli
  4. 1/16 are anticipated to be vegetation with inexperienced seeds and constricted pods, yyii.

What is dominant ?

Dominant is over the receive and thus it is the dominant character. Its include and genotypes for example red colour of flowers are dominant over white.

Thus it is clear that the above explanations are true.

To learn more about the dominant refer to the link ;

https://brainly.com/question/8368376

   

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