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During battling practice, two pop flies are hit from the same location, 2s apart the paths are modeled by the equations h equal negative 16t squared + 56t and h = -16t + 156t - 248 where t is the time that has passed since the first ball was hit

Sagot :

student1700359

Answer:

Step-by-step explanation:

To find the time at which both balls are at the same height, set the equations equal to each other then solve for t.

h = -16t^2 + 56t

h = -16t^2 + 156t - 248

-16t^2 + 56t = -16t^2 + 156t - 248

You can cancel out the -16t^2's to get

56t = 156t - 248

=> 0 = 100t - 248

=> 248 = 100t

=> 2.48 = t

Using this time value, plug into either equation to find the height.

h = 16(2.48)^2 + 56(2.48)

Final answer:

h = 40.4736

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