Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A 400-gram sample of iron, initially at 21 0Cis heated to 65 0C. Determine the energy attained (in Joules) by the iron sample if the specific heat capacity of iron is 0.11 cal/g0C

Sagot :

Answer:

Q = 8100 J.

Explanation:

Hello there!

In this case, according to the given information, we can infer this is a question about calorimetry, and we can use the general heat equation to solve this one:

[tex]Q=mC(T_2-T_1)[/tex]

Thus, we plug in the given mass, specific heat and temperatures to obtain the energy involved in this heating process:

[tex]Q=400g*0.11\frac{cal}{g\°C} (65\°C-21\°C)\\\\Q=1936cal[/tex]

Which converted to Joules turns out to be:

[tex]Q=1936cal*\frac{4.184J}{1cal} \\\\Q=8100J[/tex]

Regards!

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.