Cuál es el área de un terreno que soporta una Fatiga de 1450KgMts2 Si se le hace cargar un peso total de 300 Kg.

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01-06-2021
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Cuál es el área de un terreno que soporta una Fatiga de 1450KgMts2 Si se le hace cargar un peso total de 300 Kg.

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yersanabria yersanabria · Answer 1 · 2021-06-02T21:05:40-04:00

Answer:

El área necesaria para que un terreno que soporta una fatiga de 1450 Kilogramos por metro cuadrado soporte un peso total de 300 Kg es:

0.2068965517 m^2

O un poco más simplificado:

0.207 m^2 aproximadamente.

Explanation:

Para identificar el área requerida para soportar un peso en particular (en este caso 300 Kg), teniendo como referencia el soporte de fatiga del terreno, puedes utilizar una regla de tres simple.

Si:

1450 Kg ⇒ 1 m^2
300 Kg ⇒ x

Y luego procedes a calcular:

[tex]x =\frac{300Kg*1m^{2} }{1450Kg}[/tex] (Se cancelan las unidades de kilogramos ya que se encuentran tanto en el numerador como en el denominador)

[tex]x =\frac{300*1m^{2} }{1450}[/tex]
[tex]x =\frac{300m^{2} }{1450}[/tex]
[tex]x =\frac{6}{29}m^{2}[/tex]

Si lo transformamos a un número decimal tendríamos:

x = 0.2068965517 [tex]m^{2}[/tex]

Y dependiendo del número de cifras decimales que puedas utilizar, el resultado aproximado es:

x ≅ 0.21 [tex]m^{2}[/tex]
x ≅ 0.207 [tex]m^{2}[/tex]

Por lo tanto, puedes identificar que el área del terreno que necesitarías para soportar 300 kilogramos con la capacidad de soporte mencionada, serían 0.207 metros cuadrados aproximadamente.

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