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(-2,-3) (-1,2) write the equation in y=mx+b​

23 12 Write The Equation In Ymxb class=

Sagot :

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Answer:

y = 5x + 7

Step-by-step explanation:

(-2, -3) & (-1, 2)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(2 - (-3)) / (-1 - (-2))

Simplify the parentheses.

= (2 + 3) / (-1 + 2)

= (5) / (1)

Simplify the fraction.

5/1

= 5

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 5x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (-1, 2). Plug in the x and y values into the x and y of the standard equation.

2 = 5(-1) + b

To find b, multiply the slope and the input of x(-1)

2 = -5 + b

Now, add 5 to both sides to isolate b.

7 = b

Plug this into your standard equation.

y = 5x + 7

This is your equation.

Check this by plugging in the other point you have not checked yet (-2, -3).

y = 5x + 7

-3 = 5(-2) + 7

-3 = -10 + 7

-3 = -3

Your equation is correct.

Hope this helps!

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