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What is percentage of values available between first and third quartile of this data set (8, 7, 3, 8, 14, 15, 20)?

Sagot :

MrRoyal

Answer:

[tex]\%Pr =71.43 \%[/tex]

Step-by-step explanation:

Given

[tex]S = \{8, 7, 3, 8, 14, 15, 20\}[/tex]

[tex]n(S) = 7[/tex]

Required

Percentage of values between Q1 and Q3

We have:

[tex]S = \{8, 7, 3, 8, 14, 15, 20\}[/tex]

Sort

[tex]Sorted = \{3, 7, 8, 8, 14, 15, 20\}[/tex]

Q1 is calculated as:

[tex]Q_1 = \frac{n+1}{4}th[/tex]

[tex]Q_1 = \frac{7+1}{4}th[/tex]

[tex]Q_1 = \frac{8}{4}th[/tex]

[tex]Q_1 = 2nd[/tex]

The second element is: 7; So:

[tex]Q_1 = 7[/tex]

Q3 is calculated as:

[tex]Q_3 = 3*\frac{n+1}{4}th[/tex]

[tex]Q_3 = 3*\frac{7+1}{4}th[/tex]

[tex]Q_3 = 3*\frac{8}{4}th[/tex]

[tex]Q_3 = 3*2th[/tex]

[tex]Q_3 = 6th[/tex]

The sixth element is: 15; So:

[tex]Q_3 = 15[/tex]

From the sorted dataset, the data between Q1 and Q3 is:

[tex]Q_3&Q_1 = \{7, 8, 8, 14, 15\}[/tex]

[tex]n(Q_3&Q_1) = 5[/tex]

The percentage is:

[tex]\%Pr =\frac{n(Q_3&Q_1)}{n(S)} * 100\%[/tex]

[tex]\%Pr =\frac{5}{7} * 100\%[/tex]

[tex]\%Pr =\frac{5* 100}{7} \%[/tex]

[tex]\%Pr =\frac{500}{7} \%[/tex]

[tex]\%Pr =71.43 \%[/tex]

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