whorible
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ILL GIVE BRAINLIEST AND 10 POINTS

ILL GIVE BRAINLIEST AND 10 POINTS class=

Sagot :

Corsaquix

Answer:

[tex](7m^2+10)^2[/tex]

Step-by-step explanation:

This is a quadratic in disguise. To visualize this better, let [tex]x=m^2[/tex]. We have:

[tex]49x^2+140x+100[/tex]

To factor, we can write out the format [tex](ax+y)(bx+z)[/tex]. We're looking for numbers [tex]a[/tex], [tex]b[/tex], [tex]y[/tex], and [tex]z[/tex] such that the following is true:

  • [tex]a\cdot b=49[/tex]
  • [tex]a\cdot z+b\cdot y=140[/tex]  
  • [tex]y\cdot z=100[/tex]

We find the following numbers:

[tex]a=7,\\y=10, \\b=7, \\z=10[/tex]

Thus, we have:

[tex](7x+10)(7x+10)[/tex]

Substitute back [tex]x=m^2[/tex] to get your final answer:

[tex](7m^2+10)(7m^2+10)=\boxed{(7m^2+10)^2}[/tex]

BabyGirlAlyssa
I believe this is the answer
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