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A gas has a solubility of 0.66 g/L at 10.0 atm. What is the pressure on a 1.0 L samples that contains 1.5 g of gas

Sagot :

Answer:

"22.73 atm" is the correct answer.

Explanation:

Given:

Solubility,

[tex]S_1=0.66 \ g/L[/tex]

[tex]S_2=1.5 \ g/L[/tex]

Pressure,

[tex]P_1=10.0 \ atm[/tex]

[tex]P_2=?[/tex]

By using Henry's law,

⇒ [tex]\frac{S_1}{P_1} =\frac{S_2}{P_2}[/tex]

or,

⇒ [tex]P_2=\frac{S_2 P_1}{S_1}[/tex]

By putting the values, we get

⇒      [tex]=\frac{1.5\times 10.0}{0.66}[/tex]

⇒      [tex]=\frac{15}{0.66}[/tex]

⇒      [tex]=22.73\ atm[/tex]