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How many liters of 10% silver iodide mixed with 9 liter of a 4%silver iodide solution to get 6% solution

Sagot :

Cricetus

Answer:

The correct answer is "4.5 liters". A further explanation is provided below.

Step-by-step explanation:

Let the solution needed be "x".

then, according to the question,

⇒ [tex]4 \ percent(9)+10 \ percent(x)=6 \ percent(9+x)[/tex]

By solving the above expression, we get

⇒ [tex]0.04\times 9+0.1x=0.06\times 9+0,06\times x[/tex]

⇒                [tex]0.04 x=0.54-0.36[/tex]

⇒                [tex]0.04x=0.18[/tex]

⇒                      [tex]x=\frac{0.18}{0.04}[/tex]

⇒                         [tex]=4.5 \ liters[/tex]

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