Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

What is the molarity of a solution containing 9.0 moles of solute in 462 mL of solution

Sagot :

Answer:

[tex]\boxed {\boxed {\sf 19 \ M}}[/tex]

Explanation:

Molarity is a measure of concentration in moles per liter, so the formula is:

[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}}[/tex]

This solution has 9.0 moles of solute and 462 milliliters of solution. We must convert milliliters to liters. Remember that 1 liter contains 1000 milliliters.

Create a ratio.

  • [tex]\frac{ 1 \ L}{ 1000 \ mL}[/tex]

Multiply by the value we are converting: 462 milliliters

  • [tex]462 \ mL *\frac{ 1 \ L}{ 1000 \ mL}[/tex]
  • [tex]462 *\frac{ 1 \ L}{ 1000}[/tex]

[tex]0.462 \ L[/tex]

Now we know both values and we can solve for the molarity.

  • moles of solute= 9.0 moles
  • liters of solution = 0.462 L

[tex]molarity= \frac{9.0 \ mol}{ 0.462 \ L}[/tex]

Divide.

[tex]molarity= 19.4805195 \ mol/L[/tex]

The original measurements of moles and milliliters have 2 and 3 significant figures respectively. We have to round our answer to the least number of sig figs, which is 2 in this case.

For the number we found, that is the ones place. The 4 in the tenths place (19.4805195) tells us to leave the 9 in the ones place.

[tex]molarity= 19 \ mol/L[/tex]

1 mole per liter is equal to 1 molar or M, so our answer is equal to 19 M.

[tex]molarity \approx 19 \ M[/tex]

The molarity of the solution is approximately 19 M.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.