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1.


For the graph of the function, identify the axis of symmetry, vertex and the formula for the function.


A. Axis of symmetry: x = –0.5; Vertex: (–0.5, 0.75); f(x) = –x2 + x


B. Axis of symmetry: x = –0.5; Vertex: (–0.5, 0.75); f(x) = x2 + x + 1


C. Axis of symmetry: x = –0.5; Vertex: (–0.5, –0.75); f(x) = x2 – x + 1


D. Axis of symmetry: x = –0.5; Vertex: (–0.5, 0.75); f(x) = x2 + 2x + 1


1 For The Graph Of The Function Identify The Axis Of Symmetry Vertex And The Formula For The Function A Axis Of Symmetry X 05 Vertex 05 075 Fx X2 X B Axis Of Sy class=

Sagot :

Answer:

D. Axis of symmetry: x = –0.5; Vertex: (–0.5, 0.75); f(x) = x2 + 2x + 1

Step-by-step explanation:

A. Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Down

Vertex: Β 

( 1 /2 , 1 /4 )

Focus: Β 

( 1 /2 , 0 )

Axis of Symmetry: Β 

x

=

1

2

Directrix: Β 

y

=

1

2

x

y

βˆ’ 2

βˆ’ 6

βˆ’ 1

βˆ’ 2

1

2

1

4

1

0

2

βˆ’ 2

B. Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: Β 

( βˆ’ 1 /2 , 3 /4 )

Focus: Β 

( βˆ’ 1 /2 , 1 )

Axis of Symmetry: Β 

x

=

βˆ’

1

2

Directrix: Β 

y

=

1

2

x

y

βˆ’ 2

3

βˆ’ 1

1

βˆ’ 1

2

3

4

1

3

2

7

C. Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: Β 

( 1 /2 , 3 /4 )

Focus: Β 

( 1 /2 , 1 )

Axis of Symmetry: Β 

x

=

1

2

Directrix: Β 

y

=

1

2

x

y

βˆ’ 2

7

βˆ’ 1

3

1

2

3

4

1

1

2

3

D. Graph the parabola using the direction, vertex, focus, and axis of symmetry.

Direction: Opens Up

Vertex: Β 

( βˆ’ 1 , 0 )

Focus: Β 

( βˆ’ 1 , 1 /4 )

Axis of Symmetry: Β 

x

=

βˆ’ 1

Directrix: Β 

y

=

βˆ’ 1

4

x

y

βˆ’ 3

4

βˆ’ 2

1

βˆ’ 1

0

0

1

1

4

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View image lalamcg115
View image lalamcg115
View image lalamcg115