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100 grams of iron (Fe) reacts with sulfuric acid (H2SO4) in the following equation.

Fe + H2SO4  Fe2(SO4)3 + H2

36. The number of grams of iron (III ) sulfate [Fe2(SO4)3] that will be produced is __ grams.
a
275
b
357

Sagot :

msm555

b

b357

Answer:

2Fe +3 H2SO4  Fe2(SO4)3 + 3H2

2*56g. 3*98g➔400g. +6g

we have

2*56 g of Fe gives 400g of iron (III ) sulfate

now

100g of Fe gives=400/112*100=357g of iron (III ) sulfate

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B is your answer.!