florvlclark
Answered

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What is the probability of rolling a six-sided number cube and getting an odd number or a number less than 4?

Sagot :

MrRoyal

Answer:

[tex]Pr(Odd\ or\ <4) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

[tex]S = \{1,2,3,4,5,6\}[/tex] --- roll of a die

[tex]n(S) = 6[/tex] ---- the sample size

[tex]Odd = \{1,3,5\}[/tex]

[tex]<4 = \{1,2,3\}[/tex]

Required

[tex]Pr(Odd\ or\ <4)[/tex]

First, list out the event of odd or <4

[tex]Odd\ or\ <4 = \{1,2,3,5\}[/tex]

So, the probability is:

[tex]Pr(Odd\ or\ <4) = \frac{n(Odd\ or\ <4)}{n(S)}[/tex]

[tex]Pr(Odd\ or\ <4) = \frac{4}{6}[/tex]

Simplify

[tex]Pr(Odd\ or\ <4) = \frac{2}{3}[/tex]

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