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Sagot :
Given :
A 10.-kilogram object falls freely for a distance of 6.0 meters near Earth's
surface.
To Find :
The total kinetic energy gained by the object as it falls.
Solution :
Since, only conservative force i.e gravity is applied on the object.
So, its total energy is constant.
Total kinetic energy gained = Total potential energy gained
K.E = mgh ( Here, g is acceleration due to gravity = 9.8 m/s² )
K.E = 10 × 9.8 × 6 J
K.E = 588 J
Hence, this is the required solution.
The kinetic energy of an object is proportional to the product of its mass and the square of the velocity of the object.
The kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
What is kinetic energy?
The kinetic energy of an object is defined as the energy that it possesses due to the motion of the object.
Given that the mass m of the object is 10 kg and it falls from the height h of 6 meters near the earth's surface. The object falls vertically, so the gravitational acceleration is applied to it.
The potential energy of the object is given below.
[tex]PE = mgh[/tex]
[tex]PE = 10 \times 9.8 \times 6[/tex]
[tex]PE = 588 \;\rm J[/tex]
The total force applied to the object is due to gravity only. Hence the total energy of the object will be constant. Thus the kinetic energy of the object will be equivalent to the potential energy of the object.
Hence we can conclude that the kinetic energy of the object is 588 J. Option B shows the kinetic energy of the object.
To know more about kinetic energy, follow the link given below.
https://brainly.com/question/21288807.
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