Answered

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The largest jaw breaker in a store is spherical with a radius of 2 in. and sells for $4.00. A
store wants to make a 6 in. radius jaw breaker. How much should they charge for this
foot long jaw breaker?

Sagot :

samuelonum1

Answer:

$12

Step-by-step explanation:

Given data

Radius= 2in

cost = $4

New jaw breaker radius= 6in

cost=???

If 2 in jaw breaker cost $4

6in jaw breaker will cost x

cross multiply

6*4= 2*x

24= 2x

x= 24/2

x= $12

Hence the 6 in jawbreaker will cost $12

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