Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The largest jaw breaker in a store is spherical with a radius of 2 in. and sells for $4.00. A
store wants to make a 6 in. radius jaw breaker. How much should they charge for this
foot long jaw breaker?

Sagot :

samuelonum1

Answer:

$12

Step-by-step explanation:

Given data

Radius= 2in

cost = $4

New jaw breaker radius= 6in

cost=???

If 2 in jaw breaker cost $4

6in jaw breaker will cost x

cross multiply

6*4= 2*x

24= 2x

x= 24/2

x= $12

Hence the 6 in jawbreaker will cost $12

We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.