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Sagot :
Step-by-step explanation:
The given equation is :
[tex]-2x^2+6x+1=-3x^2[/tex]
Taking all the terms to one side of the equation i.e.
[tex]-2x^2+6x+1+3x^2=0\\\\x^2+6x+1=0[/tex]
It is a quadratic equation of the form [tex]ax^2+bx+c=0[/tex] whose solution is given by :
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
Here, a = 1, b = 6 and c = 1
Put all the values,
[tex]x=\dfrac{-6\pm \sqrt{6^2-4(1)(1)}}{2(1)}\\\\x=-0.171\ and\ x=-5.82[/tex]
Hence, this is the required solution.
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