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Sagot :
Answer:
103.9 KPa
Explanation:
From the ideal gas equation;
PV=nRT
From the parameters given;
P= ?
T=250 K
V= 60L
n=3
R=0.082 atmLK-1mol-1
P= nRT/V
P= 3 × 0.082 × 250/60
P= 1.025 atm
1 atm=101325 pascals
1.025 atm = 1.025 atm × 101325 pascals/1atm
= 103.9 KPa
Answer:
103.9kPa
Explanation:
To solve this question we must use the equation:
PV = nRT
P = nRT / V
Where P is pressure in atm
n are moles of the gas = 3mol
R is gas constant = 0.082atmL/molK
T is absolute temperature = 250K
V = 60L
P = 3mol*0.082atmL/molK*250K / 60L
P = 1.025atm
As 1atm = 101.325kPa
1.025atm * (101.325kPa / 1atm) = 103.9kPa
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