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find acute angle between the line 2x+4y=7 and x+2y=5

Sagot :

Answer:

arctan(4/3) ≈ 0.9272

Step-by-step explanation:

On comparing eqⁿ to y = mx + c,

Slope of 2x + 4y = 7 is -2/4 = - 1/2

Slope of x + 2y = 5 is - 1/2

Therefore, if A is the angle b/w them,

A = arctan | (m1 + m2)/(1 - m1m2) |

A = arctan | (-½ - ½)/(1 - ¼) |

A = arctan (4/3)