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If a point is chosen inside the square, what
is the probability that it will also be inside the
circle?
1


Sagot :

Point to be present exactly at midway between center and circumference of circle (let’s say radius = r) should lie at circumference of circle of radius r/2.

Favorable outcome = 2*pi*r/2

Total outcome = Point can be anywhere inside the circle of radius r = Area of circle = pi * r * r

Probability = (2*pi*r/2) / pi * r* r = 1/r.

Not completely sure about correctness . Waiting for comments to verify.