Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A rectangular park 60m long and 40m broad is surrounded by a path of 4m. Then the area of path will be:​

Sagot :

Answer:

A = 864 m^2

Step-by-step explanation:

For a rectangle of length L and width W, the area is given by:

A = W*L

We know that the park has:

L = 60m

W = 40m

Now, if we surround the whole park with a path that is 4m wide, then the rectangle made by the park and the path has the dimensions:

L' = 60m + 2*4m

W' = 40m + 2*4m

(as you can see in the sketch at the end)

The area of the path will be equal to the difference between the area of the rectangle made of the park + the path, and the area of the park alone.

This is:

A = L'*W' - *W

A = ( 60m + 2*4m)*(40m + 2*4m) - 60m*40m

A = 68m*48m - 60m*40m

A = 864 m^2

View image facundo3141592