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Write an inequality, in slope-intercept form, for the graph below. If necessary,
use '<="for < or ">" for >.
(-3,0)
X
5
(0, -3)
-5

Write An Inequality In Slopeintercept Form For The Graph Below If Necessary Use Ltfor Lt Or Gt For Gt 30 X 5 0 3 5 class=

Sagot :

Given:

The graph of an inequality.

To find:

The inequality in slope intercept form.

Solution:

The slope intercept form is:

[tex]y=mx+b[/tex]

Where, m is slope and b is y-intercept.

From the given graph it is clear that the boundary line passes through the points (-3,0) and (0,-3).

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-0=\dfrac{-3-0}{0-(-3)}(x-(-3))[/tex]

[tex]y=\dfrac{-3}{3}(x+3)[/tex]

[tex]y=-1(x+3)[/tex]

[tex]y=-x-3[/tex]

From the given graph it is clear that the boundary line is a solid line and the shaded region lies above the line, so the sign of inequality must be "≥".

[tex]y\geq -x-3[/tex]

Therefore, the required inequality is [tex]y\geq -x-3[/tex].

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