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Sagot :
A) let h = number of half page ads and f = number of full page ads
40h + 75f = 800. Assuming budget is fully spent
h + f = 13
B) 75h + 75f = 975 (multiplying the second equation by 75)
35h = 175 (subtracting the first equation)
h = 5
Michael purchases 5 half page adverts
C) 5 + f = 13 (Substituting for h in second equation)
f = 8
Michael purchases 8 full page adverts
40h + 75f = 800. Assuming budget is fully spent
h + f = 13
B) 75h + 75f = 975 (multiplying the second equation by 75)
35h = 175 (subtracting the first equation)
h = 5
Michael purchases 5 half page adverts
C) 5 + f = 13 (Substituting for h in second equation)
f = 8
Michael purchases 8 full page adverts
The number of half page advertisements that Michael purchased is 5 while the full page advertisements is 8.
Let the number of half page ads be represented by h
Let the number of full page ads be represented by f.
Therefore, the system of equations to represent the situation will be:
h + f = 13 ....... i
40h + 75f = 800 ........ ii
From equation i,
h = 13 - f ....... equation iii
Put the value of h into equation ii
40h + 75f = 800
40(13 - f) + 75f = 800
520 - 40f + 75f = 800
Collect like terms
75f - 40f = 800 - 520
35f = 280
f = 280/35
f = 8
The number of full-page advertisements that Michael purchased is 8.
Since h + f = 13
h + 8 = 13
h = 13 - 8
h = 5
The number of half page advertisements that Michael purchased is 5.
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