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[tex]y = {x}^{x} [/tex]
Find
[tex] \frac{dy}{dx} [/tex]


Sagot :

Answer:

[tex]y = x^x\\\\log y = x log x\\\\\frac{1}{y} \frac{dy}{dx} = x \cdot \frac{1}{x} + log x\\\\\frac{1}{y} \frac{dy}{dx} = 1 + log x\\\\\frac{dy}{dx} = y (1 + log x)\\\\\frac{dy}{dx} = x^x(1 + log x)[/tex]

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