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Find the equation (in terms of x ) of the line through the points (-3,4) and (1,-8)

Sagot :

spectrojamz

Answer:

A(-3,4) B(1,-8)

y-y1/x-x1 =y2-y1/x2-x1

y-4/x--3 = -8-4/1--3

y-4/x+3 = -12/1+3

y-4/x+3 =-12/4

y-4/x+3 = -3

y-4 = -3(x+3)

y-4=-3x-9

y+3x +9-4=

y+3x+5=0

zaradyer

Answer:

y = -3x - 5

Step-by-step explanation:

-3, 4 and 1, -8

1 - -3 = 4

-8 - 4 = -12

[tex]\frac{-12}{4}[/tex] = [tex]\frac{-3}{1}[/tex] = -3

gradient/slope = -3

now substituting in the point -3, 4 to find the y intercept:

4= -3 x -3 + c

4 = 9 + c

-5 = c

y intercept = -5

equation is y = -3x - 5

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