Answered

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Please help I will give brainliest!!!!!

Please Help I Will Give Brainliest class=

Sagot :

rvillalta2002

Answer:

Step-by-step explanation:

[tex]sin^2\theta+cos^2\theta=1~=>sin\theta=\pm\sqrt{1-cos^2\theta}\\\\cos\theta=\frac{\sqrt{2}}{2}[/tex]

we'll took the negative solucion of sin because sin is negative in IV cuadrant

[tex]sin\theta=-\sqrt{1-(\frac{\sqrt{2}}{2})^2}=-\frac{1}{\sqrt{2}}=-\frac{\sqrt{2}}{2}[/tex]

[tex]tan\theta=\frac{\sin\theta}{\cos\theta}[/tex]  => [tex]tan\theta=-1[/tex]

so, the right option is the last one

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