Kristank258
Answered

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If the function f (2) 3x2 + bx + 2 has no real roots, which of the following could be the value of b? -7, -1, 8, 0
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Sagot :

wegnerkolmp2741o

Answer:

b could be -1 or 0

Step-by-step explanation:

f(x) = 3x^2 +bx+2

if it has no real roots, the discriminant must be less than zero

b^2 -4ac <0

a=3  b=b  c=2

b^2 - 4(3)(2) <0

b^2 - 24 <0

b^2 < 24

Taking the square root of each side

b< 2 sqrt(6)  and b > 2 sqrt(6)

b could be -1 or 0

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