Answered

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Diedra rolls an unbalanced die 72 times and gets a "6" 21 times. If she rolls the die 15 more times, which of these is the most reasonable prediction of the number of times she will not roll a "6"?

Sagot :

facundo3141592

By using the relative frequency, we can expect to not roll a "6" in 11 rolls.

How many times can we expect to not roll a "6"?

We know that in a total of 72 rolls, the outcome is "6" 21 times.

Then the relative frequency is:

F = 21/72 = 0.292

Then we can expect that in N rolls, we will get (0.292)*N times a "6".

So the number of times that we will not get a 6, is:

(1 - 0.292)*N

In this case is N = 15, then we get:

(1 - 0.292)*15 = 10.62

Rounding to the next whole number we get 11, this means that we can expect to not roll a "6" in 11 rolls.

If you want to learn more about relative frequency:

https://brainly.com/question/3857836

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