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Sagot :
Answer:
By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Average of 1,200 dollars and a standard deviation of 900 dollars.
This means that [tex]\mu = 1200, \sigma = 900[/tex]
Sample of 10.
This means that [tex]n = 10, s = \frac{900}{\sqrt{10}} = 284.6[/tex]
The sampling distribution of the sample mean amount of money in a savings account is
By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.
The sampling distribution of the sample mean amount of money in a savings account is mean of 1,200 and standard deviation of 284.6 dollars.
Calculation of mean & standard deviation:
Since the distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a standard deviation of 900 dollars. And, a random sample of 10.
So here the mean should be $1,200
And, the standard deviation should be
[tex]= 900 \div \sqrt10[/tex]
= $284.6
learn more about mean here: https://brainly.com/question/9588526
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